There Are 9 Red And 6 Green Marbles

There s one blue marble.

There are 9 red and 6 green marbles.

There s two red marbles in the bag. These are clearly all yellow. There are a total of 14 green and blue marbles so the probability is 14 25 or 56. There are 35 marbles in a bag.

There are 9 red and 6 green marbles in a bag. So i could pick that red marble or that red marble. What percent of the marbles aren t blue. The total number of marbles in the box is 25 that is 9 green 5 blue and 11 red.

If we are too draw another green marble the same probability 6 15 will be resulted. 1 answer jim g. There are 9 red and 6 green marbles in a bag if a child reaches the bag randomly and picks 6. In the bag there are 6 green marbles and 12 red marbles.

So this is all the possible outcomes. The measure of probability is number of favourable outcomes total possible outcomes a favourable outcome is a green marble of which there are 6. 4 20 then find the probability of picking green again 3 19. What is the probability of drawing a green marble from the bag.

Be careful letting children play with marbles they may swallow. So i could pick that green marble or that green marble. Remember there is one less marble in the jar and that you assume the marble picked was green. Indeed we have these equations where r is the number of red marbles g is the number.

You wish to know t probability that the single chosen green or blue marble. Finally multiply the probabilities and reduce to get 3 95 share. A child reaches in the bag and randomly takes one marble. There are 6 red 4 green 5 blue and 5 yellow marbles in a jar.

What is the probability of that child getting a green marble. Jun 21 2018 1 3 explanation. There are still 6 green marbles and 9 red ones. In a jar of red green and blue marbles all but 6 are red marbles all but 8 are green and all but 4 are blue.

As both requirements have to be fulfilled the required probability is the multiplication of both 6 15 6 15. Write the probability as a fraction in simplest form a decimal and a percent. Solution from the condition we can determine how many marbles of each color were there in the jar. 7 red 5 green 6 blue pick 7 6 1 14 marbles and at least 1 is red because 14 green blue 11 at least 1 is blue because 14 red green 12 at least 1 is green because 14 red blue 13 picking 13 marbles could result in green marble absence if all 13 marbl.

9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.